Assuming that the two
16fooble items are different, the 4 right items must be a banana,
a light bulb, an eyedropper, and a saw. If the two 16fooble items
can be the same, another possibility exists: namely, the 4 right
items could be a banana, a snake, a saw, and another saw.
There are many ways to
figure this out. For those of you who are completely stumped, look
again at Player 2's visit to the City Hall. He's carrying 3 items,
and 2 of them are right. Since the light bulb and the snake can
both be right items (since they both cost 8 foobles), the
banana must be a right item. And since the banana is a right
item, no other 4fooble item can be right. And because we know that
either the light bulb or the snake is right, we know that the other
8fooble items can't be right. Thus, from Player 4's visit
to City Hall, we know that the saw must be a right item (since the
4fooble hair spray and the 8fooble toothpaste can't be right).
Get the idea?
Dont' worry if you didn't
figure out this Fooblitzky Puzzle. Players can visit the
City Hall as often as they want. In a real game, information usually
comes in bits and pieces, rather than all at once, as in this example.
